Using Shannon's algorithm for code assignment to characters of varying probabilities.

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Home » C++ Home » Algorithms Home » Using Shannon's algorithm for code assignment to characters of varying probabilities.

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Title	Using Shannon's algorithm for code assignment to characters of varying probabilities.
Author	Abhishek H. Dwivedi
Author Email	yarrows [at] indiatimes.com
Description	This code gives the binary codes to each of the characters having different probabilities of occurence,using the Shannon's algorithm. User must enter the probabilities .Make sure that the sum of all probablities is <= to 1. The character with the highest probability of occurence will be assigned the code of least length, while that of the lowest probability will be assigned the longest length. Before the codes are assigned, the characters are sorted in descending order. Hence, the results displayed also are in descending order.
Category	C++ » Algorithms
Hits	366426
Code	Select and Copy the Code
#include<stdio.h> #include<conio.h> #include<math.h> int temp,i,j,col=0,n=100,count=0,b[10][2]; float a[10],sum=100; char c[10][10]; void main() { void part(int,int); clrscr(); printf("Enter number of characters "); while(n>10) { printf("(Not more than 10) "); scanf("%d",&n); } while(sum>1) { printf("Enter their probabilities of occurences "); sum=0; for(i=1;i<=n;i++) { printf("."); scanf("%f",&a[i]); while(a[i]>=1) a[i]=a[i]/10; sum=sum+a[i]; if(sum>1) break; } if(sum>1) printf("Sum of probabilities must be less than or equal to 1 ! "); } for(i=0;i<10;i++) { for(j=0;j<10;j++) c[i][j]=''; } for(i=0;i<n;i++) { for(j=0;j<n;j++) { if(a[j]<a[j+1]) { temp=a[j]; a[j]=a[j+1]; a[j+1]=temp; }}} printf(" "); part(1,n); printf("The codes are "); for(i=0;i<n;i++) { for(j=0;j<10;j++) printf("%c ",c[i][j]); printf(" "); } getch(); } void part(int low,int high) { int min=100,k,z,sum=0,dif,sum1=0,l=0; z=(high-low); z=abs(z); for(j=0;j<10;j++) for(i=0;i<2;i++) b[j][i]=0; if(z>1) { count++; for(i=low-1;i<high;i++) sum=sum+a[i]; sum1=a[low-1]; sum=sum-a[low-1]; for(i=low;i<=high;i++) { dif=sum-sum1; sum1=a[i]+sum1; sum=sum-a[i]; b[l][0]=abs(dif); b[l][1]=i; l++; } for(i=0;i<l;i++) if(min>b[i][0]) { min=b[i][0]; k=b[i][1]; } for(i=low-1;i<k;i++) c[i][col]='0'; for(i=k;i<high;i++) c[i][col]='1'; col++; part(low,k); part(k+1,high); } else { c[low][col]='1'; c[high][col]='0'; if(c[high+1][col]==''&&high<=9) while(c[high+1][col]=='*') col--; col++; } }

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