Shortest Path - Beginners / Lab Assignments Source Code in Java

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Home » Java Home » Beginners / Lab Assignments Home » Shortest Path

A D V E R T I S E M E N T

Title	Shortest Path
Author	Shanawas P M
Author Email	james_1983_bond [at] yahoo.co.uk
Description	To find the shortest path using Breadth First Search Algorithm
Category	Java » Beginners / Lab Assignments
Hits	387695
Code	Select and Copy the Code
import java.io.; import java.util.; class shortpath { public static int x1,x2,y1,y2,n,m; public static int a[][]=new int[10][10],parent[][]=new int[10][10],dist[][]=new int[10][10],i,j; public static void main(String s[]) throws IOException { int x,y,num; LinkedList l=new LinkedList(); LinkedList path=new LinkedList(); BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); System.out.println("Enter the value for n & m 1st matrix"); BufferedReader bf=new BufferedReader(new InputStreamReader(System.in)); n=Integer.parseInt(bf.readLine()); m=Integer.parseInt(bf.readLine()); System.out.println("Enter the elements for 1st matrix(0 or 1)"); for(i=0;i<n;i++) for(j=0;j<m;j++) { a[i][j]=Integer.parseInt(bf.readLine()); parent[i][j]=-1; dist[i][j]=nm; } System.out.println("Enter the position of source(x,y)"); x1=Integer.parseInt(bf.readLine()); y1=Integer.parseInt(bf.readLine()); System.out.println("Enter the position of Destination(x,y)"); x2=Integer.parseInt(bf.readLine()); y2=Integer.parseInt(bf.readLine()); l.add(getnum(x1,y1)); dist[x1][y1]=0; while(l.size()!=0) { num=Integer.parseInt(l.removeLast().toString()); x=num/m; y=num%m; if(x>0&&a[x-1][y]!=1&&(dist[x-1][y]>(dist[x][y])+1)) { l.add(getnum(x-1,y)); dist[x-1][y]=dist[x][y]+1; parent[x-1][y]=num; } if(y>0&&a[x][y-1]!=1&&(dist[x][y-1]>(dist[x][y])+1)) { l.add(getnum(x,y-1)); dist[x][y-1]=dist[x][y]+1; parent[x][y-1]=num; } if(x<n-1&&a[x+1][y]!=1&&(dist[x+1][y]>(dist[x][y])+1)) { l.add(getnum(x+1,y)); dist[x+1][y]=dist[x][y]+1; parent[x+1][y]=num; } if(y<m-1&&a[x][y+1]!=1&&(dist[x][y+1]>(dist[x][y])+1)) { l.add(getnum(x,y+1)); dist[x][y+1]=dist[x][y]+1; parent[x][y+1]=num; } } path.add("("+x2+","+y2+")"); x=x2;y=y2; do{ num=parent[x][y]; x=num/m; y=num%m; path.add("("+x+","+y+")"); }while(!(x==x1&&y==y1)); while(path.size()!=0) System.out.println(path.removeLast()); } public static Integer getnum(int x,int y) { return new Integer(xm+y); } }

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