Universal URL check - Components Source Code in ASP

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Home » ASP Home » Components Home » Universal URL check

A D V E R T I S E M E N T

Title	Universal URL check
Description	If you let users add URLs to your site (for example links to their site) you want to check them first to make sure the URL is working. This code will do the trick! From your page the URL is posted and the result (including the URL) is posted back to the refering page.
Category	ASP » Components
Hits	364726
Code	Select and Copy the Code
'************************************ ' Name: Universal URL check ' Description:If you let users add URL's ' to your site (for example links to their ' site) you want to check them first to ma ' ke sure the URL is working. 'This code will Do the trick! 'From your page the URL is posted and the result (including the URL) is posted back To the refering page. ' ' Inputs:The checkpage will need just on ' e input value from a form. This input sh ' ould be named 'url'; '<INPUT type="text" name="url"> ' ' Returns:After the check is done, the r ' efering page is displayed again, but now ' the original url and the result is poste ' d to this page (use request.form to get ' their values). ' ' Assumes:There are 3 pages: 'check.asp To post the url and receive the result of the check. 'checkurl.asp this page will Do the check 'checkdone.asp; this page will post the results back To the referer. ' ' Side Effects:In order to make this scr ' ipt work you server should have IE 5+ in ' stalled. ' '** check.asp 'part 1: the post form '***************** <% strFrom=Request.Form("result") strResult=Request.Form("url") %> <HTML> <HEAD> <TITLE>URL check</TITLE> </HEAD> <BODY> <FORM method="post" action="checkurl.asp"> <P><Input Type="text" name="url"></P> <P><Input Type="submit" value="submit" name="submit"></P> </FORM> <P><%= strFrom %></P> <P><%= strResult %></P> </BODY> </HTML> '** checkurl.asp 'part 2: the actual check '******************** <% strURL=Request.Form("url") If strURL<>"" Then If Left(LCase(strURL),7)<>"http://" Then strURL="http://" & strURL End If On Error Resume Next Dim objHTTP Dim sHTML Set objHTTP = Server.CreateObject ("Microsoft.XMLHTTP") objHTTP.open "GET", strURL, False objHTTP.send sHTML=objHTTP.statusText If err Or sHTML<>"OK" Then sTxt="fail" Else sTxt="ok" End If Set objHTTP=Nothing Else sTxt="fail" End If strFrom=Request.ServerVariables("HTTP_REFERER") p=InStr(1,strFrom,"?") If p>0 Then strFrom=Left(strFrom,p-1) End If Response.Redirect "checkdone.asp?result=" & sTxt & "&ref=" & strURL & "&return=" & strFrom %> '** checkdone.asp 'part 3: post the results back to the re ' ferer '********************** <% strRes=Request.QueryString("result") strRef=Request.QueryString("ref") strRet=Request.QueryString("return") %> <HTML> <HEAD> </HEAD> <SCRIPT> Function postit(){ myform.submit(); } </SCRIPT> <BODY onLoad="postit()"> <FORM method="post" action="<%= strRet %>" name="myform"> <Input Type="hidden" name="result" value="<%= strRes %>"> <Input Type="hidden" name="url" value="<%= strRef %>"> </FORM> </BODY> </HTML>

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