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Title Questions asked in Company Interviews.
Author rajarathnam.l
Author Email rajara2004 [at] yahoo.co.in
Description This involves software questions asked in leading software company.

Category C » Beginners / Lab Assignments
Hits 322280
Code Select and Copy the Code
1) abcD+abcd+aBCd+aBCD > then the simplified function is > ( Capital letters are copliments of corresponding letters > A=compliment of a) > > [a] a [b] ab [c] abc [d] a(bc)* [e] mone > (bc)*=compliment of bc > > Ans: e > > ------------------------------------- > 2) A 12 address lines maps to the memory of > > [a] 1k bytes [b] 0.5k bytes [c] 2k bytes [d] none > > Ans: b > > ---------------------------------------- > 3) In a processor these are 120 instructions . Bits needed to impliment > this instructions > [a] 6 [b] 7 [c] 10 [d] none > > Ans: b > > ----------------------------------------- > 4) In 8085 microprocessor READY signal does.which of the following > is incorrect statements > [a]It is input to the microprocessor > [b] It sequences the instructions > > Ans : b > ---------------------------------------- > > 5) Return address will be returned by function to > [a] Pushes to the stack by call > Ans : a > ------------------------------------------ > 6) > n=7623 > { > temp=n/10; > result=temp*10+ result; > n=n/10 > } > > Ans : 3267 > ---------------------------------------------- > 7) If A>B then > F=F(G); > else B>C then > F=G(G); > in this , for 75% times A>B and 25% times B>C then,is 10000 instructions > are there ,then the ratio of F to G > [a] 7500:2500 [b] 7500:625 [c] 7500:625 if a=b=c else > 7500:2500 > -------------------------------------------------- > 8) In a compiler there is 36 bit for a word and to store a character 8bits are > needed. IN this to store > a character two words are appended .Then for storing a K characters string, > How many words are needed. > [a] 2k/9 [b] (2k+8)/9 [c] (k+8)/9 [d] 2*(k+8)/9 [e] none > > Ans: a > --------------------------------------------------------- > 9) C program code > > int zap(int n) > { > if(n<=1)then zap=1; > else zap=zap(n-3)+zap(n-1); > } > then the call zap(6) gives the values of zap > [a] 8 [b] 9 [c] 6 [d] 12 [e] 15 > > Ans: b > --------------------------------------------------------------- > > > PART-B > ------- > 1) Virtual memory size depends on > [a] address lines [b] data bus > [c] disc space [d] a & c [e] none > > Ans : a > ----------------------------------------------- > 2) Critical section is > [a] > [b] statements which are accessing shared resourses > Ans : b > ------------------------------------------------- > > 3) load a > mul a > store t1 > load b > mul b > store t2 > mul t2 > add t1 > > then the content in accumulator is > > Ans : a**2+b**4 > --------------------------------------------------- > 4) question (3) in old paper > 5) q(4) in old paper > 6) question (7) in old paper > 7) q(9) in old paper > ------------------------------ >

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