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Title Digit to words
Author Priyank Luthra
Author Email priyank.luthra [at] gmail.com
Description This program converts any number written in digits to equivalent word representation. eg. if i/p is 232, output is "two hundered thirty two".
Category C » Beginners / Lab Assignments
Hits 382217
Code Select and Copy the Code
Code : //Program to convert digit representation to equivalent word representation //By Priyank Luthra BE computer Engg. DCE #include<stdio.h> #include<conio.h> struct std{ int dig; char wrd[20]; }; struct std fig[]={{1,"one"},{2,"two"},{3,"three"},{4,"four"},{5,"five"},{6,"six"}, {7,"seven"},{8,"eight"},{9,"nine"},{10,"ten"},{11,"eleven"},{12,"twelve"}, {13,"thirteen"}, {14,"fourteen"},{15,"fifteen"},{16,"sixteen"},{17,"seventeen"},{18,"eighte en"},{19,"nineteen"}, {20,"twenty"},{30,"thirty"},{40,"fourty"},{50,"fifty"},{60,"sixty"},{70,"s eventy"},{80,"eighty"}, {90,"ninety"}}; int num1[5],i; op0(long num) { for(i=0;i<20;i++) if(fig[i].dig==num) printf("%s",fig[i].wrd); } op1(long num) { //num1=num; num1[0]=num/10; num1[0]=num1[0]*10; num1[1]=num%10; for(i=0;i<27;i++) {if(fig[i].dig==num1[0]) printf("%s ",fig[i].wrd); } for(i=0;i<20;i++) {if(fig[i].dig==num1[1]) printf("%s",fig[i].wrd); } } op2(long num) { int k,j=num%100; k=num/100; for(i=0;i<10;i++) {if(fig[i].dig==k) {printf("%s hundred ",fig[i].wrd); if(j>0&&j<20) op0(num%100); else op1(num%100); } } } op3(long num) { int k,j=num%1000; k=num/1000; for(i=0;i<10;i++) { if(fig[i].dig==k) { printf("%s thousand ",fig[i].wrd); if(j>=1&&j<10) op0(num%1000); else if(j>10&&j<100) op1(num%1000); else op2(num%1000); } } } op4(long num) { int k=num/1000,j; j=num%1000; if(k<=20) { op0(num/1000); printf(" thousand "); if(j>0&&j<10) op0(num%1000); if(j>10&&j<100) op1(num%1000); else op2(num%1000); } if((k>20)&&(k<100)) { op1(num/1000); printf(" thousand "); if(j>0&&j<10) op0(num%1000); if(j>10&&j<100) op1(num%1000); else op2(num%1000); } //op2(num%1000); } op5(long num) { int k=num/100000; int j=num%100000; for(i=0;i<10;i++) { if(fig[i].dig==k) { printf("%s lakh ",fig[i].wrd); if(j>0&&j<20) op0(num%100000); if(j>20&&j<100) op1(num%100000); if(j>100&&j<1000) op2(num%100000); if(j>1000&&j<10000) op3(num%100000); if(j>10000&&j<100000) op4(num%100000); } } } main() { long num; clrscr(); printf("Enter the number "); scanf("%ld",&num); if(num<=20) op0(num); if((num>20)&&(num/100==0)) op1(num); if(num==100) printf("hundred"); if(num>100&&num<1000) op2(num); if(num==1000) printf("one thousand"); if(num>1000&&num<10000) op3(num); if(num==10000) printf("ten thousand"); if(num>10000&&num<100000) op4(num); if(num==100000) printf("one lakh"); if(num>100000&&num<1000000) op5(num); if(num==1000000) printf("One crore"); getch(); }

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